Solve 2m^4n^2*3m^3n^9

$$2 m ^ { 4 } n ^ { 2 } \cdot 3 m ^ { 3 } n ^ { 9 }$$

Evaluate

$$6m^{7}n^{11}$$

Steps Using Commutative Property of Multiplication

Use the rules of exponents to simplify the expression.

$$2^{1}m^{4}n^{2}\times 3^{1}m^{3}n^{9}$$

Use the Commutative Property of Multiplication.

$$2^{1}\times 3^{1}m^{4}m^{3}n^{2}n^{9}$$

To multiply powers of the same base, add their exponents.

$$2^{1}\times 3^{1}m^{4+3}n^{2+9}$$

Add the exponents 4 and 3.

$$2^{1}\times 3^{1}m^{7}n^{2+9}$$

Add the exponents 2 and 9.

$$2^{1}\times 3^{1}m^{7}n^{11}$$

Multiply 2 times 3.

$$6m^{7}n^{11}$$

Differentiate w.r.t. m

$$42m^{6}n^{11}$$