2 m = - d m
Solve for d
\left\{\begin{matrix}\\d=-2\text{, }&\text{unconditionally}\\d\in \mathrm{R}\text{, }&m=0\end{matrix}\right.
Solve for m
\left\{\begin{matrix}\\m=0\text{, }&\text{unconditionally}\\m\in \mathrm{R}\text{, }&d=-2\end{matrix}\right.
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\left(-d\right)m=2m
Swap sides so that all variable terms are on the left hand side.
-dm=2m
Reorder the terms.
\left(-m\right)d=2m
The equation is in standard form.
\frac{\left(-m\right)d}{-m}=\frac{2m}{-m}
Divide both sides by -m.
d=\frac{2m}{-m}
Dividing by -m undoes the multiplication by -m.
d=-2
Divide 2m by -m.
2m-\left(-d\right)m=0
Subtract \left(-d\right)m from both sides.
2m+dm=0
Multiply -1 and -1 to get 1.
\left(2+d\right)m=0
Combine all terms containing m.
\left(d+2\right)m=0
The equation is in standard form.
m=0
Divide 0 by 2+d.
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