Solve 2k-1/8[-6k-2(k-4)]

$$2 k - \frac { 1 } { 8 } [ - 6 k - 2 ( k - 4 ) ]$$

Evaluate

$$3k-1$$

Solution Steps

Use the distributive property to multiply -2 by k-4.

$$2k-\frac{1}{8}\left(-6k-2k+8\right)$$

Combine -6k and -2k to get -8k.

$$2k-\frac{1}{8}\left(-8k+8\right)$$

Use the distributive property to multiply -\frac{1}{8} by -8k+8.

$$2k-\frac{1}{8}\left(-8\right)k-\frac{1}{8}\times 8$$

Express -\frac{1}{8}\left(-8\right) as a single fraction.

$$2k+\frac{-\left(-8\right)}{8}k-\frac{1}{8}\times 8$$

Multiply -1 and -8 to get 8.

$$2k+\frac{8}{8}k-\frac{1}{8}\times 8$$

Divide 8 by 8 to get 1.

$$2k+1k-\frac{1}{8}\times 8$$

Cancel out 8 and 8.

$$2k+1k-1$$

Combine 2k and 1k to get 3k.

$$3k-1$$

Expand

$$3k-1$$

Solution Steps

Use the distributive property to multiply -2 by k-4.

$$2k-\frac{1}{8}\left(-6k-2k+8\right)$$

Combine -6k and -2k to get -8k.

$$2k-\frac{1}{8}\left(-8k+8\right)$$

Use the distributive property to multiply -\frac{1}{8} by -8k+8.

$$2k-\frac{1}{8}\left(-8\right)k-\frac{1}{8}\times 8$$

Express -\frac{1}{8}\left(-8\right) as a single fraction.

$$2k+\frac{-\left(-8\right)}{8}k-\frac{1}{8}\times 8$$

Multiply -1 and -8 to get 8.

$$2k+\frac{8}{8}k-\frac{1}{8}\times 8$$

Divide 8 by 8 to get 1.

$$2k+1k-\frac{1}{8}\times 8$$

Cancel out 8 and 8.

$$2k+1k-1$$

Combine 2k and 1k to get 3k.

$$3k-1$$