Factor
\left(k-2\right)\left(2k^{2}+5\right)
Evaluate
\left(k-2\right)\left(2k^{2}+5\right)
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2k^{2}\left(k-2\right)+5\left(k-2\right)
Do the grouping 2k^{3}-4k^{2}+5k-10=\left(2k^{3}-4k^{2}\right)+\left(5k-10\right), and factor out 2k^{2} in the first and 5 in the second group.
\left(k-2\right)\left(2k^{2}+5\right)
Factor out common term k-2 by using distributive property. Polynomial 2k^{2}+5 is not factored since it does not have any rational roots.
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