Solve 2b-3+a(b)+6=0

$$2 b - 3 + a ( b ) + 6 = 0$$

Solve for a

$$a=-2-\frac{3}{b}$$

$$b\neq 0$$

Steps for Solving Linear Equation

Add -3 and 6 to get 3.

$$2b+3+ab=0$$

Subtract 2b from both sides. Anything subtracted from zero gives its negation.

$$3+ab=-2b$$

Subtract 3 from both sides.

$$ab=-2b-3$$

The equation is in standard form.

$$ba=-2b-3$$

Divide both sides by b.

$$\frac{ba}{b}=\frac{-2b-3}{b}$$

Dividing by b undoes the multiplication by b.

$$a=\frac{-2b-3}{b}$$

Divide -2b-3 by b.

$$a=-2-\frac{3}{b}$$

Solve for b

$$b=-\frac{3}{a+2}$$

$$a\neq -2$$

Steps for Solving Linear Equation

Add -3 and 6 to get 3.

$$2b+3+ab=0$$

Subtract 3 from both sides. Anything subtracted from zero gives its negation.

$$2b+ab=-3$$

Combine all terms containing b.

$$\left(2+a\right)b=-3$$

The equation is in standard form.

$$\left(a+2\right)b=-3$$

Divide both sides by 2+a.

$$\frac{\left(a+2\right)b}{a+2}=-\frac{3}{a+2}$$

Dividing by 2+a undoes the multiplication by 2+a.

$$b=-\frac{3}{a+2}$$