Solve 2ax-b=10

$$2 a x - b = 10$$

Solve for a (complex solution)

$$\left\{\begin{matrix}a=\frac{b+10}{2x}\text{, }&x\neq 0\\a\in \mathrm{C}\text{, }&b=-10\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Add b to both sides.

$$2ax=10+b$$

The equation is in standard form.

$$2xa=b+10$$

Divide both sides by 2x.

$$\frac{2xa}{2x}=\frac{b+10}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$a=\frac{b+10}{2x}$$

Solve for a

$$\left\{\begin{matrix}a=\frac{b+10}{2x}\text{, }&x\neq 0\\a\in \mathrm{R}\text{, }&b=-10\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Add b to both sides.

$$2ax=10+b$$

The equation is in standard form.

$$2xa=b+10$$

Divide both sides by 2x.

$$\frac{2xa}{2x}=\frac{b+10}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$a=\frac{b+10}{2x}$$

Solve for b

$$b=2\left(ax-5\right)$$

Steps for Solving Linear Equation

Subtract 2ax from both sides.

$$-b=10-2ax$$

Divide both sides by -1.

$$\frac{-b}{-1}=\frac{10-2ax}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$b=\frac{10-2ax}{-1}$$

Divide 10-2ax by -1.

$$b=2ax-10$$