Solve 2ax+3a+b=2ax+2b+3

$$2 a x + 3 a + b = 2 a x + 2 b + 3$$

Solve for a

$$a=\frac{b+3}{3}$$

Steps for Solving Linear Equation

Subtract 2ax from both sides.

$$2ax+3a+b-2ax=2b+3$$

Combine 2ax and -2ax to get 0.

$$3a+b=2b+3$$

Subtract b from both sides.

$$3a=2b+3-b$$

Combine 2b and -b to get b.

$$3a=b+3$$

Divide both sides by 3.

$$\frac{3a}{3}=\frac{b+3}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$a=\frac{b+3}{3}$$

Divide b+3 by 3.

$$a=\frac{b}{3}+1$$

Solve for b

$$b=3\left(a-1\right)$$

Steps for Solving Linear Equation

Subtract 2b from both sides.

$$2ax+3a+b-2b=2ax+3$$

Combine b and -2b to get -b.

$$2ax+3a-b=2ax+3$$

Subtract 2ax from both sides.

$$3a-b=2ax+3-2ax$$

Combine 2ax and -2ax to get 0.

$$3a-b=3$$

Subtract 3a from both sides.

$$-b=3-3a$$

Divide both sides by -1.

$$\frac{-b}{-1}=\frac{3-3a}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$b=\frac{3-3a}{-1}$$

Divide 3-3a by -1.

$$b=3a-3$$