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2a\left(cb^{2}-1\right)+3b\left(cb^{2}-1\right)-4c\left(cb^{2}-1\right)
Do the grouping 2ab^{2}c-2a+3b^{3}c-3b-4b^{2}c^{2}+4c=\left(2ab^{2}c-2a\right)+\left(3b^{3}c-3b\right)+\left(-4b^{2}c^{2}+4c\right), and factor out 2a,3b,-4c in each of the groups respectively.
\left(cb^{2}-1\right)\left(2a+3b-4c\right)
Factor out common term cb^{2}-1 by using distributive property.