Solve 2ab+64b=0

$$2 a b + 64 b = 0$$

Solve for a

$$\left\{\begin{matrix}\\a=-32\text{, }&\text{unconditionally}\\a\in \mathrm{R}\text{, }&b=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 64b from both sides. Anything subtracted from zero gives its negation.

$$2ab=-64b$$

The equation is in standard form.

$$2ba=-64b$$

Divide both sides by 2b.

$$\frac{2ba}{2b}=-\frac{64b}{2b}$$

Dividing by 2b undoes the multiplication by 2b.

$$a=-\frac{64b}{2b}$$

Divide -64b by 2b.

$$a=-32$$

Solve for b

$$\left\{\begin{matrix}\\b=0\text{, }&\text{unconditionally}\\b\in \mathrm{R}\text{, }&a=-32\end{matrix}\right.$$

Steps for Solving Linear Equation

Combine all terms containing b.

$$\left(2a+64\right)b=0$$

Divide 0 by 2a+64.

$$b=0$$