Solve for a
a=\frac{3b}{2}+2
Solve for b
b=\frac{2\left(a-2\right)}{3}
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2a=4+3b
Add 3b to both sides.
2a=3b+4
The equation is in standard form.
\frac{2a}{2}=\frac{3b+4}{2}
Divide both sides by 2.
a=\frac{3b+4}{2}
Dividing by 2 undoes the multiplication by 2.
a=\frac{3b}{2}+2
Divide 4+3b by 2.
-3b=4-2a
Subtract 2a from both sides.
\frac{-3b}{-3}=\frac{4-2a}{-3}
Divide both sides by -3.
b=\frac{4-2a}{-3}
Dividing by -3 undoes the multiplication by -3.
b=\frac{2a-4}{3}
Divide 4-2a by -3.
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