Solve for a
a=\frac{3b}{2}
Solve for b
b=\frac{2a}{3}
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2a=3b
Add 3b to both sides. Anything plus zero gives itself.
\frac{2a}{2}=\frac{3b}{2}
Divide both sides by 2.
a=\frac{3b}{2}
Dividing by 2 undoes the multiplication by 2.
-3b=-2a
Subtract 2a from both sides. Anything subtracted from zero gives its negation.
\frac{-3b}{-3}=-\frac{2a}{-3}
Divide both sides by -3.
b=-\frac{2a}{-3}
Dividing by -3 undoes the multiplication by -3.
b=\frac{2a}{3}
Divide -2a by -3.
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Matrix
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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