Solve for a
a=\frac{3b}{2}-2c
Solve for b
b=\frac{2\left(a+2c\right)}{3}
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2a=3b-4c
The equation is in standard form.
\frac{2a}{2}=\frac{3b-4c}{2}
Divide both sides by 2.
a=\frac{3b-4c}{2}
Dividing by 2 undoes the multiplication by 2.
a=\frac{3b}{2}-2c
Divide 3b-4c by 2.
3b-4c=2a
Swap sides so that all variable terms are on the left hand side.
3b=2a+4c
Add 4c to both sides.
\frac{3b}{3}=\frac{2a+4c}{3}
Divide both sides by 3.
b=\frac{2a+4c}{3}
Dividing by 3 undoes the multiplication by 3.
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