Solve for a
a=\frac{22^{r}-6}{2}
Solve for r
r=\log_{22}\left(2\left(a+3\right)\right)
a>-3
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2a=22^{r}-6
Subtract 6 from both sides.
\frac{2a}{2}=\frac{22^{r}-6}{2}
Divide both sides by 2.
a=\frac{22^{r}-6}{2}
Dividing by 2 undoes the multiplication by 2.
a=\frac{22^{r}}{2}-3
Divide 22^{r}-6 by 2.
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