Solve for a
a=-\frac{c}{2}-\frac{5b}{2}+50
Solve for b
b=-\frac{c}{5}-\frac{2a}{5}+20
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2a+c=100-5b
Subtract 5b from both sides.
2a=100-5b-c
Subtract c from both sides.
2a=100-c-5b
The equation is in standard form.
\frac{2a}{2}=\frac{100-c-5b}{2}
Divide both sides by 2.
a=\frac{100-c-5b}{2}
Dividing by 2 undoes the multiplication by 2.
a=-\frac{c}{2}-\frac{5b}{2}+50
Divide 100-5b-c by 2.
5b+c=100-2a
Subtract 2a from both sides.
5b=100-2a-c
Subtract c from both sides.
5b=100-c-2a
The equation is in standard form.
\frac{5b}{5}=\frac{100-c-2a}{5}
Divide both sides by 5.
b=\frac{100-c-2a}{5}
Dividing by 5 undoes the multiplication by 5.
b=-\frac{c}{5}-\frac{2a}{5}+20
Divide 100-2a-c by 5.
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