Solve 2-xgeq11/9

$$2 - x \geq \frac { 11 } { 9 }$$

Solve for x

$$x\leq \frac{7}{9}$$

Solution Steps

Subtract 2 from both sides.

$$-x\geq \frac{11}{9}-2$$

Convert 2 to fraction \frac{18}{9}.

$$-x\geq \frac{11}{9}-\frac{18}{9}$$

Since \frac{11}{9} and \frac{18}{9} have the same denominator, subtract them by subtracting their numerators.

$$-x\geq \frac{11-18}{9}$$

Subtract 18 from 11 to get -7.

$$-x\geq -\frac{7}{9}$$

Divide both sides by -1. Since -1 is negative, the inequality direction is changed.

$$x\leq \frac{-\frac{7}{9}}{-1}$$

Express \frac{-\frac{7}{9}}{-1} as a single fraction.

$$x\leq \frac{-7}{9\left(-1\right)}$$

Multiply 9 and -1 to get -9.

$$x\leq \frac{-7}{-9}$$

Fraction \frac{-7}{-9} can be simplified to \frac{7}{9} by removing the negative sign from both the numerator and the denominator.

$$x\leq \frac{7}{9}$$