Solve 2-8+-2-3--12+-6x-2

$$2 - 8 + - 2 - 3 - - 12 + - 6 x - 2$$

Evaluate

$$-6x-1$$

Solution Steps

Subtract 8 from 2 to get -6.

$$-6-2-3-\left(-12\right)-6x-2$$

Subtract 2 from -6 to get -8.

$$-8-3-\left(-12\right)-6x-2$$

Subtract 3 from -8 to get -11.

$$-11-\left(-12\right)-6x-2$$

The opposite of -12 is 12.

$$-11+12-6x-2$$

Add -11 and 12 to get 1.

$$1-6x-2$$

Subtract 2 from 1 to get -1.

$$-1-6x$$

Differentiate w.r.t. x

$$-6$$

Steps Using Derivative Rule for Sum

Subtract 8 from 2 to get -6.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-6-2-3-\left(-12\right)-6x-2)$$

Subtract 2 from -6 to get -8.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-8-3-\left(-12\right)-6x-2)$$

Subtract 3 from -8 to get -11.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-11-\left(-12\right)-6x-2)$$

The opposite of -12 is 12.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-11+12-6x-2)$$

Add -11 and 12 to get 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(1-6x-2)$$

Subtract 2 from 1 to get -1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-1-6x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-6x^{1-1}$$

Subtract 1 from 1.

$$-6x^{0}$$

For any term t except 0, t^{0}=1.

$$-6$$