Solve for x
x\geq \frac{4}{3}
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-4-6x\leq -12
Subtract 6 from 2 to get -4.
-6x\leq -12+4
Add 4 to both sides.
-6x\leq -8
Add -12 and 4 to get -8.
x\geq \frac{-8}{-6}
Divide both sides by -6. Since -6 is negative, the inequality direction is changed.
x\geq \frac{4}{3}
Reduce the fraction \frac{-8}{-6} to lowest terms by extracting and canceling out -2.
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