Solve 2(x+y)^2+(x+y)-3=

$$2 ( x + y ) ^ { 2 } + ( x + y ) - 3 =$$

Evaluate

$$2\left(x+y\right)^{2}+x+y-3$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+y\right)^{2}.

$$2\left(x^{2}+2xy+y^{2}\right)+x+y-3$$

Use the distributive property to multiply 2 by x^{2}+2xy+y^{2}.

$$2x^{2}+4xy+2y^{2}+x+y-3$$

Expand

$$2x^{2}+4xy+x+2y^{2}+y-3$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+y\right)^{2}.

$$2\left(x^{2}+2xy+y^{2}\right)+x+y-3$$

Use the distributive property to multiply 2 by x^{2}+2xy+y^{2}.

$$2x^{2}+4xy+2y^{2}+x+y-3$$