Solve 2(x+1)^2=4.5

$$2 ( x + 1 ) ^ { 2 } = 4.5$$

Solve for x

$$x=0.5$$

$$x=-2.5$$

Steps by Finding Square Root

Divide both sides by 2.

$$\frac{2\left(x+1\right)^{2}}{2}=\frac{4.5}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$\left(x+1\right)^{2}=\frac{4.5}{2}$$

Divide 4.5 by 2.

$$\left(x+1\right)^{2}=2.25$$

Take the square root of both sides of the equation.

$$x+1=\frac{3}{2} x+1=-\frac{3}{2}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{3}{2}-1 x+1-1=-\frac{3}{2}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{3}{2}-1 x=-\frac{3}{2}-1$$

Subtract 1 from \frac{3}{2}.

$$x=\frac{1}{2}$$

Subtract 1 from -\frac{3}{2}.

$$x=-\frac{5}{2}$$

The equation is now solved.

$$x=\frac{1}{2} x=-\frac{5}{2}$$