Solve 2(m-3)-4(m+B)=0

$$2 ( m - 3 ) - 4 ( m + B ) = 0$$

Solve for B

$$B=\frac{-m-3}{2}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by m-3.

$$2m-6-4\left(m+B\right)=0$$

Use the distributive property to multiply -4 by m+B.

$$2m-6-4m-4B=0$$

Combine 2m and -4m to get -2m.

$$-2m-6-4B=0$$

Add 2m to both sides. Anything plus zero gives itself.

$$-6-4B=2m$$

Add 6 to both sides.

$$-4B=2m+6$$

Divide both sides by -4.

$$\frac{-4B}{-4}=\frac{2m+6}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$B=\frac{2m+6}{-4}$$

Divide 6+2m by -4.

$$B=\frac{-m-3}{2}$$

Solve for m

$$m=-2B-3$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by m-3.

$$2m-6-4\left(m+B\right)=0$$

Use the distributive property to multiply -4 by m+B.

$$2m-6-4m-4B=0$$

Combine 2m and -4m to get -2m.

$$-2m-6-4B=0$$

Add 6 to both sides. Anything plus zero gives itself.

$$-2m-4B=6$$

Add 4B to both sides.

$$-2m=6+4B$$

The equation is in standard form.

$$-2m=4B+6$$

Divide both sides by -2.

$$\frac{-2m}{-2}=\frac{4B+6}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$m=\frac{4B+6}{-2}$$

Divide 6+4B by -2.

$$m=-2B-3$$