Solve 2(c+b)=5c-3

$$2 ( c + b ) = 5 c - 3$$

Solve for b

$$b=\frac{3\left(c-1\right)}{2}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by c+b.

$$2c+2b=5c-3$$

Subtract 2c from both sides.

$$2b=5c-3-2c$$

Combine 5c and -2c to get 3c.

$$2b=3c-3$$

Divide both sides by 2.

$$\frac{2b}{2}=\frac{3c-3}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$b=\frac{3c-3}{2}$$

Solve for c

$$c=\frac{2b}{3}+1$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by c+b.

$$2c+2b=5c-3$$

Subtract 5c from both sides.

$$2c+2b-5c=-3$$

Combine 2c and -5c to get -3c.

$$-3c+2b=-3$$

Subtract 2b from both sides.

$$-3c=-3-2b$$

The equation is in standard form.

$$-3c=-2b-3$$

Divide both sides by -3.

$$\frac{-3c}{-3}=\frac{-2b-3}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$c=\frac{-2b-3}{-3}$$

Divide -3-2b by -3.

$$c=\frac{2b}{3}+1$$