Solve for a
a=3-\frac{10}{x}
x\neq 0
Solve for x
x=-\frac{10}{a-3}
a\neq 3
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2ax+20-6x=0
Use the distributive property to multiply 2 by ax+10.
2ax-6x=-20
Subtract 20 from both sides. Anything subtracted from zero gives its negation.
2ax=-20+6x
Add 6x to both sides.
2xa=6x-20
The equation is in standard form.
\frac{2xa}{2x}=\frac{6x-20}{2x}
Divide both sides by 2x.
a=\frac{6x-20}{2x}
Dividing by 2x undoes the multiplication by 2x.
a=3-\frac{10}{x}
Divide -20+6x by 2x.
2ax+20-6x=0
Use the distributive property to multiply 2 by ax+10.
2ax-6x=-20
Subtract 20 from both sides. Anything subtracted from zero gives its negation.
\left(2a-6\right)x=-20
Combine all terms containing x.
\frac{\left(2a-6\right)x}{2a-6}=-\frac{20}{2a-6}
Divide both sides by 2a-6.
x=-\frac{20}{2a-6}
Dividing by 2a-6 undoes the multiplication by 2a-6.
x=-\frac{10}{a-3}
Divide -20 by 2a-6.
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