Solve 2(4-3^2)-8+sqrt[3]{125}+2^3+2

$$2 ( 4 - 3 ^ { 2 } ) - 8 + \sqrt[ 3 ] { 125 } + 2 ^ { 3 } + 2$$

Evaluate

$$-3$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$2\left(4-9\right)-8+\sqrt[3]{125}+2^{3}+2$$

Subtract 9 from 4 to get -5.

$$2\left(-5\right)-8+\sqrt[3]{125}+2^{3}+2$$

Multiply 2 and -5 to get -10.

$$-10-8+\sqrt[3]{125}+2^{3}+2$$

Subtract 8 from -10 to get -18.

$$-18+\sqrt[3]{125}+2^{3}+2$$

Calculate \sqrt[3]{125} and get 5.

$$-18+5+2^{3}+2$$

Add -18 and 5 to get -13.

$$-13+2^{3}+2$$

Calculate 2 to the power of 3 and get 8.

$$-13+8+2$$

Add -13 and 8 to get -5.

$$-5+2$$

Add -5 and 2 to get -3.

$$-3$$

Factor

$$-3$$