Solve 2(3/4)(4)+b

$$2 ( 3 / 4 ) ( 4 ) + b$$

Evaluate

$$b+6$$

Solution Steps

Express 2\times \frac{3}{4} as a single fraction.

$$\frac{2\times 3}{4}\times 4+b$$

Multiply 2 and 3 to get 6.

$$\frac{6}{4}\times 4+b$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}\times 4+b$$

Express \frac{3}{2}\times 4 as a single fraction.

$$\frac{3\times 4}{2}+b$$

Multiply 3 and 4 to get 12.

$$\frac{12}{2}+b$$

Divide 12 by 2 to get 6.

$$6+b$$

Differentiate w.r.t. b

$$1$$

Steps Using Derivative Rule for Sum

Express 2\times \frac{3}{4} as a single fraction.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{2\times 3}{4}\times 4+b)$$

Multiply 2 and 3 to get 6.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{6}{4}\times 4+b)$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{3}{2}\times 4+b)$$

Express \frac{3}{2}\times 4 as a single fraction.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{3\times 4}{2}+b)$$

Multiply 3 and 4 to get 12.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{12}{2}+b)$$

Divide 12 by 2 to get 6.

$$\frac{\mathrm{d}}{\mathrm{d}b}(6+b)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$b^{1-1}$$

Subtract 1 from 1.

$$b^{0}$$

For any term t except 0, t^{0}=1.

$$1$$