Solve 2(-1)^3-k(-1)^2+3(-1)+10=0

$$2 ( - 1 ) ^ { 3 } - k ( - 1 ) ^ { 2 } + 3 ( - 1 ) + 10 = 0$$

Solve for k

$$k=5$$

Steps for Solving Linear Equation

Calculate -1 to the power of 3 and get -1.

$$2\left(-1\right)-k\left(-1\right)^{2}+3\left(-1\right)+10=0$$

Multiply 2 and -1 to get -2.

$$-2-k\left(-1\right)^{2}+3\left(-1\right)+10=0$$

Calculate -1 to the power of 2 and get 1.

$$-2-k\times 1+3\left(-1\right)+10=0$$

Multiply 3 and -1 to get -3.

$$-2-k\times 1-3+10=0$$

Add -3 and 10 to get 7.

$$-2-k\times 1+7=0$$

Subtract 7 from both sides. Anything subtracted from zero gives its negation.

$$-2-k\times 1=-7$$

Reorder the terms.

$$-2-k=-7$$

Add 2 to both sides.

$$-k=-7+2$$

Add -7 and 2 to get -5.

$$-k=-5$$

Multiply both sides by -1.

$$k=5$$