Skip to main content
Factor
Tick mark Image
Evaluate
Tick mark Image
Graph

Similar Problems from Web Search

Share

x\left(2x^{2}-5x+3\right)
Factor out x.
a+b=-5 ab=2\times 3=6
Consider 2x^{2}-5x+3. Factor the expression by grouping. First, the expression needs to be rewritten as 2x^{2}+ax+bx+3. To find a and b, set up a system to be solved.
-1,-6 -2,-3
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 6.
-1-6=-7 -2-3=-5
Calculate the sum for each pair.
a=-3 b=-2
The solution is the pair that gives sum -5.
\left(2x^{2}-3x\right)+\left(-2x+3\right)
Rewrite 2x^{2}-5x+3 as \left(2x^{2}-3x\right)+\left(-2x+3\right).
x\left(2x-3\right)-\left(2x-3\right)
Factor out x in the first and -1 in the second group.
\left(2x-3\right)\left(x-1\right)
Factor out common term 2x-3 by using distributive property.
x\left(2x-3\right)\left(x-1\right)
Rewrite the complete factored expression.