Solve 2x^3+x-1divx-4

$$2 { x }^{ 3 } +x-1 \div x-4$$

Evaluate

$$2x^{3}+x-4-\frac{1}{x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 2x^{3}+x-4 times \frac{x}{x}.

$$\frac{\left(2x^{3}+x-4\right)x}{x}-\frac{1}{x}$$

Since \frac{\left(2x^{3}+x-4\right)x}{x} and \frac{1}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(2x^{3}+x-4\right)x-1}{x}$$

Do the multiplications in \left(2x^{3}+x-4\right)x-1.

$$\frac{2x^{4}+x^{2}-4x-1}{x}$$

Factor

$$\frac{2x^{4}+x^{2}-4x-1}{x}$$