Solve 2x^2-x-1=x^2-5x-(-1-x^2)

$$2 { x }^{ 2 } -x-1= { x }^{ 2 } -5x-(-1- { x }^{ 2 } )$$

Solve for x

$$x=\frac{1}{2}=0.5$$

Steps for Solving Linear Equation

To find the opposite of -1-x^{2}, find the opposite of each term.

$$2x^{2}-x-1=x^{2}-5x+1+x^{2}$$

Combine x^{2} and x^{2} to get 2x^{2}.

$$2x^{2}-x-1=2x^{2}-5x+1$$

Subtract 2x^{2} from both sides.

$$2x^{2}-x-1-2x^{2}=-5x+1$$

Combine 2x^{2} and -2x^{2} to get 0.

$$-x-1=-5x+1$$

Add 5x to both sides.

$$-x-1+5x=1$$

Combine -x and 5x to get 4x.

$$4x-1=1$$

Add 1 to both sides.

$$4x=1+1$$

Add 1 and 1 to get 2.

$$4x=2$$

Divide both sides by 4.

$$x=\frac{2}{4}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$x=\frac{1}{2}$$