Solve 2x^2-3x-6=x^2-4x-(2-x^2)

$$2 { x }^{ 2 } -3x-6= { x }^{ 2 } -4x-(2- { x }^{ 2 } )$$

Solve for x

$$x=4$$

Steps for Solving Linear Equation

To find the opposite of 2-x^{2}, find the opposite of each term.

$$2x^{2}-3x-6=x^{2}-4x-2+x^{2}$$

Combine x^{2} and x^{2} to get 2x^{2}.

$$2x^{2}-3x-6=2x^{2}-4x-2$$

Subtract 2x^{2} from both sides.

$$2x^{2}-3x-6-2x^{2}=-4x-2$$

Combine 2x^{2} and -2x^{2} to get 0.

$$-3x-6=-4x-2$$

Add 4x to both sides.

$$-3x-6+4x=-2$$

Combine -3x and 4x to get x.

$$x-6=-2$$

Add 6 to both sides.

$$x=-2+6$$

Add -2 and 6 to get 4.

$$x=4$$