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factor(-x^{2}-50x+75)
Combine 2x^{2} and -3x^{2} to get -x^{2}.
-x^{2}-50x+75=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-\left(-50\right)±\sqrt{\left(-50\right)^{2}-4\left(-1\right)\times 75}}{2\left(-1\right)}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-50\right)±\sqrt{2500-4\left(-1\right)\times 75}}{2\left(-1\right)}
Square -50.
x=\frac{-\left(-50\right)±\sqrt{2500+4\times 75}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{-\left(-50\right)±\sqrt{2500+300}}{2\left(-1\right)}
Multiply 4 times 75.
x=\frac{-\left(-50\right)±\sqrt{2800}}{2\left(-1\right)}
Add 2500 to 300.
x=\frac{-\left(-50\right)±20\sqrt{7}}{2\left(-1\right)}
Take the square root of 2800.
x=\frac{50±20\sqrt{7}}{2\left(-1\right)}
The opposite of -50 is 50.
x=\frac{50±20\sqrt{7}}{-2}
Multiply 2 times -1.
x=\frac{20\sqrt{7}+50}{-2}
Now solve the equation x=\frac{50±20\sqrt{7}}{-2} when ± is plus. Add 50 to 20\sqrt{7}.
x=-10\sqrt{7}-25
Divide 50+20\sqrt{7} by -2.
x=\frac{50-20\sqrt{7}}{-2}
Now solve the equation x=\frac{50±20\sqrt{7}}{-2} when ± is minus. Subtract 20\sqrt{7} from 50.
x=10\sqrt{7}-25
Divide 50-20\sqrt{7} by -2.
-x^{2}-50x+75=-\left(x-\left(-10\sqrt{7}-25\right)\right)\left(x-\left(10\sqrt{7}-25\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -25-10\sqrt{7} for x_{1} and -25+10\sqrt{7} for x_{2}.
-x^{2}-50x+75
Combine 2x^{2} and -3x^{2} to get -x^{2}.