Solve 2x^2-12x-8

$$2 { x }^{ 2 } -12x-8$$

Factor

$$2\left(x-\left(3-\sqrt{13}\right)\right)\left(x-\left(\sqrt{13}+3\right)\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$2x^{2}-12x-8=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-\left(-12\right)±\sqrt{\left(-12\right)^{2}-4\times 2\left(-8\right)}}{2\times 2}$$

Square -12.

$$x=\frac{-\left(-12\right)±\sqrt{144-4\times 2\left(-8\right)}}{2\times 2}$$

Multiply -4 times 2.

$$x=\frac{-\left(-12\right)±\sqrt{144-8\left(-8\right)}}{2\times 2}$$

Multiply -8 times -8.

$$x=\frac{-\left(-12\right)±\sqrt{144+64}}{2\times 2}$$

Add 144 to 64.

$$x=\frac{-\left(-12\right)±\sqrt{208}}{2\times 2}$$

Take the square root of 208.

$$x=\frac{-\left(-12\right)±4\sqrt{13}}{2\times 2}$$

The opposite of -12 is 12.

$$x=\frac{12±4\sqrt{13}}{2\times 2}$$

Multiply 2 times 2.

$$x=\frac{12±4\sqrt{13}}{4}$$

Now solve the equation x=\frac{12±4\sqrt{13}}{4} when ± is plus. Add 12 to 4\sqrt{13}.

$$x=\frac{4\sqrt{13}+12}{4}$$

Divide 12+4\sqrt{13} by 4.

$$x=\sqrt{13}+3$$

Now solve the equation x=\frac{12±4\sqrt{13}}{4} when ± is minus. Subtract 4\sqrt{13} from 12.

$$x=\frac{12-4\sqrt{13}}{4}$$

Divide 12-4\sqrt{13} by 4.

$$x=3-\sqrt{13}$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 3+\sqrt{13} for x_{1} and 3-\sqrt{13} for x_{2}.

$$2x^{2}-12x-8=2\left(x-\left(\sqrt{13}+3\right)\right)\left(x-\left(3-\sqrt{13}\right)\right)$$

Evaluate

$$2\left(x^{2}-6x-4\right)$$