Solve 2x^2-x^2-32+16

$$2 { x }^{ 2 } - { x }^{ 2 } -32+16$$

Evaluate

$$x^{2}-16$$

Solution Steps

Combine 2x^{2} and -x^{2} to get x^{2}.

$$x^{2}-32+16$$

Add -32 and 16 to get -16.

$$x^{2}-16$$

Factor

$$\left(x-4\right)\left(x+4\right)$$

Solution Steps

Multiply and combine like terms.

$$x^{2}-16$$

Rewrite x^{2}-16 as x^{2}-4^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(x-4\right)\left(x+4\right)$$