Solve 23^2+3x-1

$$2 { 3 }^{ 2 } +3x-1$$

Evaluate

$$3x+17$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$2\times 9+3x-1$$

Multiply 2 and 9 to get 18.

$$18+3x-1$$

Subtract 1 from 18 to get 17.

$$17+3x$$

Differentiate w.r.t. x

$$3$$

Steps Using Derivative Rule for Sum

Calculate 3 to the power of 2 and get 9.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2\times 9+3x-1)$$

Multiply 2 and 9 to get 18.

$$\frac{\mathrm{d}}{\mathrm{d}x}(18+3x-1)$$

Subtract 1 from 18 to get 17.

$$\frac{\mathrm{d}}{\mathrm{d}x}(17+3x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$3x^{1-1}$$

Subtract 1 from 1.

$$3x^{0}$$

For any term t except 0, t^{0}=1.

$$3\times 1$$

For any term t, t\times 1=t and 1t=t.

$$3$$