Solve 2*2^3-3*2^2+1-2^3+3*2^2-2

$$2 \times 2 ^ { 3 } - 3 \times 2 ^ { 2 } + 1 - 2 ^ { 3 } + 3 \times 2 ^ { 2 } - 2$$

Evaluate

$$7$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$2^{4}-3\times 2^{2}+1-2^{3}+3\times 2^{2}-2$$

Calculate 2 to the power of 4 and get 16.

$$16-3\times 2^{2}+1-2^{3}+3\times 2^{2}-2$$

Calculate 2 to the power of 2 and get 4.

$$16-3\times 4+1-2^{3}+3\times 2^{2}-2$$

Multiply 3 and 4 to get 12.

$$16-12+1-2^{3}+3\times 2^{2}-2$$

Subtract 12 from 16 to get 4.

$$4+1-2^{3}+3\times 2^{2}-2$$

Add 4 and 1 to get 5.

$$5-2^{3}+3\times 2^{2}-2$$

Calculate 2 to the power of 3 and get 8.

$$5-8+3\times 2^{2}-2$$

Subtract 8 from 5 to get -3.

$$-3+3\times 2^{2}-2$$

Calculate 2 to the power of 2 and get 4.

$$-3+3\times 4-2$$

Multiply 3 and 4 to get 12.

$$-3+12-2$$

Add -3 and 12 to get 9.

$$9-2$$

Subtract 2 from 9 to get 7.

$$7$$

Factor

$$7$$