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2\left(-\sqrt{2}\right)+2\sqrt{2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
-2\sqrt{2}+2\sqrt{2}
Multiply 2 and -1 to get -2.
0
Combine -2\sqrt{2} and 2\sqrt{2} to get 0.