Solve 2*9*-1/3+1/3

$$2 \times 9 \times - \frac{ 1 }{ 3 } + \frac{ 1 }{ 3 }$$

Evaluate

$$-\frac{17}{3}\approx -5.666666667$$

Solution Steps

Multiply 2 and 9 to get 18.

$$18\left(-\frac{1}{3}\right)+\frac{1}{3}$$

Express 18\left(-\frac{1}{3}\right) as a single fraction.

$$\frac{18\left(-1\right)}{3}+\frac{1}{3}$$

Multiply 18 and -1 to get -18.

$$\frac{-18}{3}+\frac{1}{3}$$

Divide -18 by 3 to get -6.

$$-6+\frac{1}{3}$$

Convert -6 to fraction -\frac{18}{3}.

$$-\frac{18}{3}+\frac{1}{3}$$

Since -\frac{18}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{-18+1}{3}$$

Add -18 and 1 to get -17.

$$-\frac{17}{3}$$

Factor

$$-\frac{17}{3} = -5\frac{2}{3} = -5.666666666666667$$