Solve 2*(-4^3)*left(lfloor2*16rfloorright)^7

$$2 \times ( { -4 }^{ 3 } ) \times { \left( \lfloor 2 \times 16 \rfloor \right) }^{ 7 }$$

Evaluate

$$-4398046511104$$

Solution Steps

Calculate -4 to the power of 3 and get -64.

$$2\left(-64\right)\left(\lfloor 2\times 16\rfloor \right)^{7}$$

Multiply 2 and -64 to get -128.

$$-128\left(\lfloor 2\times 16\rfloor \right)^{7}$$

Multiply 2 and 16 to get 32.

$$-128\left(\lfloor 32\rfloor \right)^{7}$$

The floor of a real number a is the largest integer number less than or equal to a. The floor of 32 is 32.

$$-128\times 32^{7}$$

Calculate 32 to the power of 7 and get 34359738368.

$$-128\times 34359738368$$

Multiply -128 and 34359738368 to get -4398046511104.

$$-4398046511104$$

Factor

$$-4398046511104$$