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2\sqrt{3}\left(\frac{\sqrt{6}}{\left(\sqrt{6}\right)^{2}}+\frac{\sqrt{3}}{\sqrt{2}}\right)
Rationalize the denominator of \frac{1}{\sqrt{6}} by multiplying numerator and denominator by \sqrt{6}.
2\sqrt{3}\left(\frac{\sqrt{6}}{6}+\frac{\sqrt{3}}{\sqrt{2}}\right)
The square of \sqrt{6} is 6.
2\sqrt{3}\left(\frac{\sqrt{6}}{6}+\frac{\sqrt{3}\sqrt{2}}{\left(\sqrt{2}\right)^{2}}\right)
Rationalize the denominator of \frac{\sqrt{3}}{\sqrt{2}} by multiplying numerator and denominator by \sqrt{2}.
2\sqrt{3}\left(\frac{\sqrt{6}}{6}+\frac{\sqrt{3}\sqrt{2}}{2}\right)
The square of \sqrt{2} is 2.
2\sqrt{3}\left(\frac{\sqrt{6}}{6}+\frac{\sqrt{6}}{2}\right)
To multiply \sqrt{3} and \sqrt{2}, multiply the numbers under the square root.
2\sqrt{3}\times \frac{2}{3}\sqrt{6}
Combine \frac{\sqrt{6}}{6} and \frac{\sqrt{6}}{2} to get \frac{2}{3}\sqrt{6}.
\frac{2\times 2}{3}\sqrt{3}\sqrt{6}
Express 2\times \frac{2}{3} as a single fraction.
\frac{4}{3}\sqrt{3}\sqrt{6}
Multiply 2 and 2 to get 4.
\frac{4}{3}\sqrt{3}\sqrt{3}\sqrt{2}
Factor 6=3\times 2. Rewrite the square root of the product \sqrt{3\times 2} as the product of square roots \sqrt{3}\sqrt{2}.
\frac{4}{3}\times 3\sqrt{2}
Multiply \sqrt{3} and \sqrt{3} to get 3.
4\sqrt{2}
Cancel out 3 and 3.