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2\sqrt{5}-3\times 3\sqrt{5}
Factor 45=3^{2}\times 5. Rewrite the square root of the product \sqrt{3^{2}\times 5} as the product of square roots \sqrt{3^{2}}\sqrt{5}. Take the square root of 3^{2}.
2\sqrt{5}-9\sqrt{5}
Multiply -3 and 3 to get -9.
-7\sqrt{5}
Combine 2\sqrt{5} and -9\sqrt{5} to get -7\sqrt{5}.