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2\times 3\sqrt{2}-6\sqrt{2}+3
Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.
6\sqrt{2}-6\sqrt{2}+3
Multiply 2 and 3 to get 6.
3
Combine 6\sqrt{2} and -6\sqrt{2} to get 0.
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