Solve 2quad2x+3/5-7x=9(3x-1)/2+4

$$2 \quad \frac { 2 x + 3 } { 5 } - 7 x = \frac { 9 ( 3 x - 1 ) } { 2 } + 4$$

Solve for x

$$x=\frac{17}{197}\approx 0.086294416$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 10, the least common multiple of 5,2.

$$4\left(2x+3\right)-70x=5\times 9\left(3x-1\right)+40$$

Use the distributive property to multiply 4 by 2x+3.

$$8x+12-70x=5\times 9\left(3x-1\right)+40$$

Combine 8x and -70x to get -62x.

$$-62x+12=5\times 9\left(3x-1\right)+40$$

Multiply 5 and 9 to get 45.

$$-62x+12=45\left(3x-1\right)+40$$

Use the distributive property to multiply 45 by 3x-1.

$$-62x+12=135x-45+40$$

Add -45 and 40 to get -5.

$$-62x+12=135x-5$$

Subtract 135x from both sides.

$$-62x+12-135x=-5$$

Combine -62x and -135x to get -197x.

$$-197x+12=-5$$

Subtract 12 from both sides.

$$-197x=-5-12$$

Subtract 12 from -5 to get -17.

$$-197x=-17$$

Divide both sides by -197.

$$x=\frac{-17}{-197}$$

Fraction \frac{-17}{-197} can be simplified to \frac{17}{197} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{17}{197}$$