Solve 2log(2)=log(2)+log(6-4)

$$2 \log ( 2 ) = \log ( 2 ) + \log ( 6-4 )$$

Verify

Solution Steps

Subtract 4 from 6 to get 2.

$$2\log_{10}\left(2\right)=\log_{10}\left(2\right)+\log_{10}\left(2\right)$$

Combine \log_{10}\left(2\right) and \log_{10}\left(2\right) to get 2\log_{10}\left(2\right).

$$2\log_{10}\left(2\right)=2\log_{10}\left(2\right)$$

Subtract 2\log_{10}\left(2\right) from both sides.

$$2\log_{10}\left(2\right)-2\log_{10}\left(2\right)=0$$

Combine 2\log_{10}\left(2\right) and -2\log_{10}\left(2\right) to get 0.

$$0=0$$

Compare 0 and 0.

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