Solve 2left(a+b+cright)=(a+b+ck

$$2 \left( a+b+c \right) =(a+b+ck$$

Solve for a

$$a=ck-b-2c$$

Solution Steps

Use the distributive property to multiply 2 by a+b+c.

$$2a+2b+2c=a+b+ck$$

Subtract a from both sides.

$$2a+2b+2c-a=b+ck$$

Combine 2a and -a to get a.

$$a+2b+2c=b+ck$$

Subtract 2b from both sides.

$$a+2c=b+ck-2b$$

Combine b and -2b to get -b.

$$a+2c=-b+ck$$

Subtract 2c from both sides.

$$a=-b+ck-2c$$

Solve for b

$$b=ck-a-2c$$

Solution Steps

Use the distributive property to multiply 2 by a+b+c.

$$2a+2b+2c=a+b+ck$$

Subtract b from both sides.

$$2a+2b+2c-b=a+ck$$

Combine 2b and -b to get b.

$$2a+b+2c=a+ck$$

Subtract 2a from both sides.

$$b+2c=a+ck-2a$$

Combine a and -2a to get -a.

$$b+2c=-a+ck$$

Subtract 2c from both sides.

$$b=-a+ck-2c$$