Solve 21/213/4-21/3

$$2 \frac{ 1 }{ 2 } 1 \frac{ 3 }{ 4 } -2 \frac{ 1 }{ 3 }$$

Evaluate

$$\frac{49}{24}\approx 2.041666667$$

Solution Steps

Multiply 2 and 2 to get 4.

$$\frac{4+1}{2}\times \frac{1\times 4+3}{4}-\frac{2\times 3+1}{3}$$

Add 4 and 1 to get 5.

$$\frac{5}{2}\times \frac{1\times 4+3}{4}-\frac{2\times 3+1}{3}$$

Multiply 1 and 4 to get 4.

$$\frac{5}{2}\times \frac{4+3}{4}-\frac{2\times 3+1}{3}$$

Add 4 and 3 to get 7.

$$\frac{5}{2}\times \frac{7}{4}-\frac{2\times 3+1}{3}$$

Multiply \frac{5}{2} times \frac{7}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\times 7}{2\times 4}-\frac{2\times 3+1}{3}$$

Do the multiplications in the fraction \frac{5\times 7}{2\times 4}.

$$\frac{35}{8}-\frac{2\times 3+1}{3}$$

Multiply 2 and 3 to get 6.

$$\frac{35}{8}-\frac{6+1}{3}$$

Add 6 and 1 to get 7.

$$\frac{35}{8}-\frac{7}{3}$$

Least common multiple of 8 and 3 is 24. Convert \frac{35}{8} and \frac{7}{3} to fractions with denominator 24.

$$\frac{105}{24}-\frac{56}{24}$$

Since \frac{105}{24} and \frac{56}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{105-56}{24}$$

Subtract 56 from 105 to get 49.

$$\frac{49}{24}$$

Factor

$$\frac{7 ^ {2}}{2 ^ {3} \cdot 3} = 2\frac{1}{24} = 2.0416666666666665$$