Solve 21/2+31/6-41/3

$$2 \frac{ 1 }{ 2 } +3 \frac{ 1 }{ 6 } -4 \frac{ 1 }{ 3 }$$

Evaluate

$$\frac{4}{3}\approx 1.333333333$$

Solution Steps

Multiply 2 and 2 to get 4.

$$\frac{4+1}{2}+\frac{3\times 6+1}{6}-\frac{4\times 3+1}{3}$$

Add 4 and 1 to get 5.

$$\frac{5}{2}+\frac{3\times 6+1}{6}-\frac{4\times 3+1}{3}$$

Multiply 3 and 6 to get 18.

$$\frac{5}{2}+\frac{18+1}{6}-\frac{4\times 3+1}{3}$$

Add 18 and 1 to get 19.

$$\frac{5}{2}+\frac{19}{6}-\frac{4\times 3+1}{3}$$

Least common multiple of 2 and 6 is 6. Convert \frac{5}{2} and \frac{19}{6} to fractions with denominator 6.

$$\frac{15}{6}+\frac{19}{6}-\frac{4\times 3+1}{3}$$

Since \frac{15}{6} and \frac{19}{6} have the same denominator, add them by adding their numerators.

$$\frac{15+19}{6}-\frac{4\times 3+1}{3}$$

Add 15 and 19 to get 34.

$$\frac{34}{6}-\frac{4\times 3+1}{3}$$

Reduce the fraction \frac{34}{6} to lowest terms by extracting and canceling out 2.

$$\frac{17}{3}-\frac{4\times 3+1}{3}$$

Multiply 4 and 3 to get 12.

$$\frac{17}{3}-\frac{12+1}{3}$$

Add 12 and 1 to get 13.

$$\frac{17}{3}-\frac{13}{3}$$

Since \frac{17}{3} and \frac{13}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{17-13}{3}$$

Subtract 13 from 17 to get 4.

$$\frac{4}{3}$$

Factor

$$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$$