Solve 2-47/3+x=-10

$$2 \frac{ -47 }{ 3 } +x=-10$$

Solve for x

$$x = \frac{64}{3} = 21\frac{1}{3} \approx 21.333333333$$

Steps for Solving Linear Equation

Fraction \frac{-47}{3} can be rewritten as -\frac{47}{3} by extracting the negative sign.

$$2\left(-\frac{47}{3}\right)+x=-10$$

Express 2\left(-\frac{47}{3}\right) as a single fraction.

$$\frac{2\left(-47\right)}{3}+x=-10$$

Multiply 2 and -47 to get -94.

$$\frac{-94}{3}+x=-10$$

Fraction \frac{-94}{3} can be rewritten as -\frac{94}{3} by extracting the negative sign.

$$-\frac{94}{3}+x=-10$$

Add \frac{94}{3} to both sides.

$$x=-10+\frac{94}{3}$$

Convert -10 to fraction -\frac{30}{3}.

$$x=-\frac{30}{3}+\frac{94}{3}$$

Since -\frac{30}{3} and \frac{94}{3} have the same denominator, add them by adding their numerators.

$$x=\frac{-30+94}{3}$$

Add -30 and 94 to get 64.

$$x=\frac{64}{3}$$