Solve 27/9div(-37/81)-3/5=

$$2 \frac { 7 } { 9 } \div ( - 3 \frac { 7 } { 81 } ) - \frac { 3 } { 5 } =$$

Evaluate

$$-\frac{3}{2}=-1.5$$

Solution Steps

Multiply 2 and 9 to get 18.

$$\frac{\frac{18+7}{9}}{-\frac{3\times 81+7}{81}}-\frac{3}{5}$$

Add 18 and 7 to get 25.

$$\frac{\frac{25}{9}}{-\frac{3\times 81+7}{81}}-\frac{3}{5}$$

Multiply 3 and 81 to get 243.

$$\frac{\frac{25}{9}}{-\frac{243+7}{81}}-\frac{3}{5}$$

Add 243 and 7 to get 250.

$$\frac{\frac{25}{9}}{-\frac{250}{81}}-\frac{3}{5}$$

Divide \frac{25}{9} by -\frac{250}{81} by multiplying \frac{25}{9} by the reciprocal of -\frac{250}{81}.

$$\frac{25}{9}\left(-\frac{81}{250}\right)-\frac{3}{5}$$

Multiply \frac{25}{9} times -\frac{81}{250} by multiplying numerator times numerator and denominator times denominator.

$$\frac{25\left(-81\right)}{9\times 250}-\frac{3}{5}$$

Do the multiplications in the fraction \frac{25\left(-81\right)}{9\times 250}.

$$\frac{-2025}{2250}-\frac{3}{5}$$

Reduce the fraction \frac{-2025}{2250} to lowest terms by extracting and canceling out 225.

$$-\frac{9}{10}-\frac{3}{5}$$

Least common multiple of 10 and 5 is 10. Convert -\frac{9}{10} and \frac{3}{5} to fractions with denominator 10.

$$-\frac{9}{10}-\frac{6}{10}$$

Since -\frac{9}{10} and \frac{6}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-9-6}{10}$$

Subtract 6 from -9 to get -15.

$$\frac{-15}{10}$$

Reduce the fraction \frac{-15}{10} to lowest terms by extracting and canceling out 5.

$$-\frac{3}{2}$$

Factor

$$-\frac{3}{2} = -1\frac{1}{2} = -1.5$$