Solve 27/10div33/5div11/2

$$2 \frac { 7 } { 10 } \div 3 \frac { 3 } { 5 } \div 1 \frac { 1 } { 2 }$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Divide \frac{\frac{2\times 10+7}{10}}{\frac{3\times 5+3}{5}} by \frac{1\times 2+1}{2} by multiplying \frac{\frac{2\times 10+7}{10}}{\frac{3\times 5+3}{5}} by the reciprocal of \frac{1\times 2+1}{2}.

$$\frac{\frac{2\times 10+7}{10}\times 2}{\frac{3\times 5+3}{5}\left(1\times 2+1\right)}$$

Multiply 2 and 10 to get 20.

$$\frac{\frac{20+7}{10}\times 2}{\frac{3\times 5+3}{5}\left(1\times 2+1\right)}$$

Add 20 and 7 to get 27.

$$\frac{\frac{27}{10}\times 2}{\frac{3\times 5+3}{5}\left(1\times 2+1\right)}$$

Express \frac{27}{10}\times 2 as a single fraction.

$$\frac{\frac{27\times 2}{10}}{\frac{3\times 5+3}{5}\left(1\times 2+1\right)}$$

Multiply 27 and 2 to get 54.

$$\frac{\frac{54}{10}}{\frac{3\times 5+3}{5}\left(1\times 2+1\right)}$$

Reduce the fraction \frac{54}{10} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{27}{5}}{\frac{3\times 5+3}{5}\left(1\times 2+1\right)}$$

Multiply 3 and 5 to get 15.

$$\frac{\frac{27}{5}}{\frac{15+3}{5}\left(1\times 2+1\right)}$$

Add 15 and 3 to get 18.

$$\frac{\frac{27}{5}}{\frac{18}{5}\left(1\times 2+1\right)}$$

Multiply 1 and 2 to get 2.

$$\frac{\frac{27}{5}}{\frac{18}{5}\left(2+1\right)}$$

Add 2 and 1 to get 3.

$$\frac{\frac{27}{5}}{\frac{18}{5}\times 3}$$

Express \frac{18}{5}\times 3 as a single fraction.

$$\frac{\frac{27}{5}}{\frac{18\times 3}{5}}$$

Multiply 18 and 3 to get 54.

$$\frac{\frac{27}{5}}{\frac{54}{5}}$$

Divide \frac{27}{5} by \frac{54}{5} by multiplying \frac{27}{5} by the reciprocal of \frac{54}{5}.

$$\frac{27}{5}\times \frac{5}{54}$$

Multiply \frac{27}{5} times \frac{5}{54} by multiplying numerator times numerator and denominator times denominator.

$$\frac{27\times 5}{5\times 54}$$

Cancel out 5 in both numerator and denominator.

$$\frac{27}{54}$$

Reduce the fraction \frac{27}{54} to lowest terms by extracting and canceling out 27.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$