Solve 25/6*(-11/2)*6/17div(-2/3)

$$2 \frac { 5 } { 6 } \times ( - 1 \frac { 1 } { 2 } ) \times \frac { 6 } { 17 } \div ( - \frac { 2 } { 3 } )$$

Evaluate

$$\frac{9}{4}=2.25$$

Solution Steps

Multiply 2 and 6 to get 12.

$$\frac{\frac{12+5}{6}\left(-\frac{1\times 2+1}{2}\right)\times \frac{6}{17}}{-\frac{2}{3}}$$

Add 12 and 5 to get 17.

$$\frac{\frac{17}{6}\left(-\frac{1\times 2+1}{2}\right)\times \frac{6}{17}}{-\frac{2}{3}}$$

Multiply 1 and 2 to get 2.

$$\frac{\frac{17}{6}\left(-\frac{2+1}{2}\right)\times \frac{6}{17}}{-\frac{2}{3}}$$

Add 2 and 1 to get 3.

$$\frac{\frac{17}{6}\left(-\frac{3}{2}\right)\times \frac{6}{17}}{-\frac{2}{3}}$$

Multiply \frac{17}{6} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{17\left(-3\right)}{6\times 2}\times \frac{6}{17}}{-\frac{2}{3}}$$

Do the multiplications in the fraction \frac{17\left(-3\right)}{6\times 2}.

$$\frac{\frac{-51}{12}\times \frac{6}{17}}{-\frac{2}{3}}$$

Reduce the fraction \frac{-51}{12} to lowest terms by extracting and canceling out 3.

$$\frac{-\frac{17}{4}\times \frac{6}{17}}{-\frac{2}{3}}$$

Multiply -\frac{17}{4} times \frac{6}{17} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{-17\times 6}{4\times 17}}{-\frac{2}{3}}$$

Do the multiplications in the fraction \frac{-17\times 6}{4\times 17}.

$$\frac{\frac{-102}{68}}{-\frac{2}{3}}$$

Reduce the fraction \frac{-102}{68} to lowest terms by extracting and canceling out 34.

$$\frac{-\frac{3}{2}}{-\frac{2}{3}}$$

Divide -\frac{3}{2} by -\frac{2}{3} by multiplying -\frac{3}{2} by the reciprocal of -\frac{2}{3}.

$$-\frac{3}{2}\left(-\frac{3}{2}\right)$$

Multiply -\frac{3}{2} times -\frac{3}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3\left(-3\right)}{2\times 2}$$

Do the multiplications in the fraction \frac{-3\left(-3\right)}{2\times 2}.

$$\frac{9}{4}$$

Factor

$$\frac{3 ^ {2}}{2 ^ {2}} = 2\frac{1}{4} = 2.25$$