Solve 23/4-49/12

$$2 \frac { 3 } { 4 } - \frac { 49 } { 12 }$$

Evaluate

$$-\frac{4}{3}\approx -1.333333333$$

Solution Steps

Multiply 2 and 4 to get 8.

$$\frac{8+3}{4}-\frac{49}{12}$$

Add 8 and 3 to get 11.

$$\frac{11}{4}-\frac{49}{12}$$

Least common multiple of 4 and 12 is 12. Convert \frac{11}{4} and \frac{49}{12} to fractions with denominator 12.

$$\frac{33}{12}-\frac{49}{12}$$

Since \frac{33}{12} and \frac{49}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{33-49}{12}$$

Subtract 49 from 33 to get -16.

$$\frac{-16}{12}$$

Reduce the fraction \frac{-16}{12} to lowest terms by extracting and canceling out 4.

$$-\frac{4}{3}$$

Factor

$$-\frac{4}{3} = -1\frac{1}{3} = -1.3333333333333333$$